Electron Configuration Practice: Rules, Examples & Quiz

Electron Configuration Practice: Rules, Examples & Quiz

electron configuration practice
electron configuration practice
✓ Expert Reviewed by Dr. Irfan Mansuri  |  Last Updated: July 2026
By Dr. Irfan Mansuri
Updated: July 8, 2026
9 min read
High School / Introductory University
Orbital filling order and electron configuration rules — a complete visual guide for chemistry students

There are two ways students approach electron configuration practice. Some memorize the filling order by rote and hope for the best on test day. Others understand the three underlying rules so well that they can reconstruct any configuration from scratch, even for transition metals and ions, without a cheat sheet. One approach takes minutes to learn but fails under pressure. The other takes an hour to master and holds up for life.

In my experience teaching chemistry to thousands of students, the second approach wins every time. This guide gives you both the rules and the practice to make them automatic.

After reading this guide, you will be able to:

  • State and apply all three electron configuration rules correctly
  • Write full and noble-gas shorthand configurations for any main-group or transition-metal element
  • Handle common exceptions like Cr and Cu without confusion
  • Write configurations for cations and anions
  • Spot and fix the five most common student mistakes
Core Idea: Every electron configuration question tests the same three rules. Learn the rules deeply, not just the answers, and every practice problem becomes straightforward.

TL;DR – Quick Summary

  • Three rules govern all electron configurations: Aufbau, Pauli, Hund’s.
  • Fill subshells in energy order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p…
  • Each orbital holds exactly 2 electrons with opposite spins (Pauli).
  • Half-fill all orbitals in a subshell before pairing any (Hund’s).
  • Cr and Cu are the most tested exceptions — memorize them.
  • For ions: remove/add electrons from the highest energy level first.

Two Approaches to Electron Configuration

The rote-memorization approach gives you a list of configurations to copy. It breaks the moment an exam asks about an element you did not memorize, or asks you to write the configuration of an ion or an excited state. The rule-based approach takes slightly longer to learn, but it generates the correct answer for every element, every ion, and every exception.

Here is a direct comparison of the two approaches so you can see exactly what you are choosing between:

Approach comparison: Rote memorization vs. Rule-based understanding
Factor Rote Memorization Rule-Based Understanding
Time to learn 30 min (for common elements) 60-90 min (rules + practice)
Works for all 118 elements No Yes
Works for ions (Fe2+, Cl-) No Yes
Handles exceptions (Cr, Cu) Only if memorized separately Yes, with one extra rule
Survives exam pressure Fragile Robust
Connects to periodic table trends No Yes
Recommended No Yes

The rest of this guide is built entirely around the rule-based approach. Let’s start with the rules themselves.

The Three Rules: A Comparison Table

All electron configuration practice reduces to three rules. Each rule answers a different question about where electrons go. Understanding what each rule does — and what it does NOT do — prevents most student errors.

The three electron configuration rules side by side
Rule Question It Answers Key Statement Max electrons per subshell Applies to orbitals of same subshell?
Aufbau Principle Which subshell fills first? Fill lowest energy subshell first s=2, p=6, d=10, f=14 No — governs subshell order
Pauli Exclusion Principle How many electrons per orbital? Max 2 per orbital; opposite spins 2 per orbital Yes — governs pairing within an orbital
Hund’s Rule How to fill orbitals within a subshell? One electron per orbital before pairing; parallel spins N/A (governs distribution) Yes — governs distribution across orbitals
► MY POV:

In my experience, the single biggest source of confusion is students mixing up Pauli and Hund’s. Pauli tells you the maximum per orbital (2, opposite spins). Hund’s tells you how to spread electrons across multiple orbitals of the same subshell. They answer completely different questions. Keep them separate in your mind and half your mistakes disappear immediately.

What Is Electron Configuration?

An electron configuration is a notation that shows how electrons are distributed among the energy subshells of an atom. It tells you exactly how many electrons occupy each subshell, written in the form: subshell notation + superscript count.

For example, carbon (atomic number 6) has the configuration: 1s² 2s² 2p². This means 2 electrons in the 1s subshell, 2 in the 2s subshell, and 2 in the 2p subshell. The total is 6, matching the atomic number.

Notation breakdown for 1s²:
1 = principal quantum number (energy level / shell)
s = subshell type (s, p, d, or f)
2 = number of electrons in that subshell

Electron configurations matter because they predict chemical behavior, bonding patterns, magnetic properties, and an element’s position on the periodic table. Every trend you study in chemistry — ionization energy, atomic radius, electronegativity — traces back to electron configuration.

The Aufbau Principle and Filling Order

The Aufbau principle (from the German word for “building up”) states that electrons occupy the lowest available energy subshell first. The energy order does not follow a simple numerical sequence, which is why students need a memory tool.

The correct filling order is:

Filling Order: 1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → 5s → 4d → 5p → 6s → 4f → 5d → 6p → 7s → 5f → 6d → 7p

Notice that 4s fills before 3d, and 6s fills before 4f. This surprises many students. The reason is that 4s has slightly lower energy than 3d in a neutral atom, so it fills first.

DIAGONAL ARROW MNEMONIC — Aufbau Filling Order
  1s
  2s  2p
  3s  3p  3d
  4s  4p  4d  4f
  5s  5p  5d  5f
  6s  6p  6d
  7s  7p

  Read diagonally from top-right to bottom-left:
  1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → 5s → 4d → 5p → 6s → 4f → 5d → 6p → 7s...
  

Each subshell holds a fixed maximum number of electrons: s holds 2, p holds 6, d holds 10, and f holds 14. These numbers come from the number of orbitals in each subshell (1, 3, 5, and 7 orbitals respectively) multiplied by 2 (Pauli’s limit per orbital).

Pauli Exclusion Principle and Hund’s Rule

Once you know the filling order, two more rules govern exactly how electrons occupy individual orbitals within each subshell.

Pauli Exclusion Principle

No two electrons in the same atom can share all four quantum numbers. In practical terms: each orbital holds a maximum of two electrons, and those two electrons must have opposite spins. You represent this in orbital box notation as one arrow pointing up and one pointing down inside the same box.

Correct (Pauli-compliant): [↑↓]    Wrong (Pauli violation): [↑↑]

Hund’s Rule

When filling orbitals within the same subshell (for example, the three 2p orbitals), place one electron in each orbital before placing a second electron in any orbital. All singly occupied orbitals must have the same spin direction (parallel spins). This minimizes electron-electron repulsion and produces the most stable arrangement.

Nitrogen (N) — 2p subshell (3 electrons):
Correct (Hund’s): [↑] [↑] [↑]
Wrong (Hund’s violation): [↑↓] [↑] [ ]
► MY POV:

I always tell my students to think of Hund’s rule like seating on a bus. If there are empty rows, no one sits next to a stranger. Electrons behave the same way — they spread out into empty orbitals before sharing. Once you have that mental image, Hund’s rule becomes impossible to forget.

Step-by-Step: How to Write Any Configuration

Follow these seven steps for any element and you will get the correct configuration every time.

  1. Find the atomic number. This equals the total number of electrons in a neutral atom.
  2. Write out the Aufbau filling order. Use the diagonal mnemonic if needed.
  3. Fill each subshell in order until you have placed all electrons. Respect the capacity limits (s=2, p=6, d=10, f=14).
  4. Apply Hund’s rule within each subshell: one electron per orbital before pairing.
  5. Apply Pauli’s principle when pairing: opposite spins only.
  6. Check for exceptions (Cr, Cu, Mo, Ag, and a few others). If the element is one of these, adjust accordingly.
  7. Optionally condense using noble gas shorthand for speed.

Worked Examples (H to Fe)

Let’s apply the steps to real elements. These cover the range of difficulty you will encounter in most courses.

Electron configurations for common elements — worked examples
Element Atomic No. Full Configuration Noble Gas Shorthand Valence Electrons
Hydrogen (H) 1 1s¹ 1s¹ 1
Helium (He) 2 1s² 1s² 2
Carbon (C) 6 1s² 2s² 2p² [He] 2s² 2p² 4
Nitrogen (N) 7 1s² 2s² 2p³ [He] 2s² 2p³ 5
Oxygen (O) 8 1s² 2s² 2p⁴ [He] 2s² 2p⁴ 6
Sodium (Na) 11 1s² 2s² 2p⁶ 3s¹ [Ne] 3s¹ 1
Sulfur (S) 16 1s² 2s² 2p⁶ 3s² 3p⁴ [Ne] 3s² 3p⁴ 6
Calcium (Ca) 20 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² [Ar] 4s² 2
Iron (Fe) 26 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶ [Ar] 3d⁶ 4s² 2 (outer) / 8 (d+s)

For iron, notice that 4s² is written after 3d⁶ in the noble gas shorthand. This is the conventional way to write transition metal configurations — list the d subshell before the s subshell in the shorthand, even though 4s filled first.

ORBITAL BOX DIAGRAM — Iron (Fe, Z=26) — 3d and 4s subshells
  3d subshell (5 orbitals, 6 electrons — Hund's rule applied):
  [ ↑↓ ] [ ↑ ] [ ↑ ] [ ↑ ] [ ↑ ]
   3d      3d    3d    3d    3d

  4s subshell (1 orbital, 2 electrons):
  [ ↑↓ ]
    4s

  Result: [Ar] 3d6 4s2
  (One 3d orbital is paired; the other four hold single electrons)
  

Noble Gas Shorthand

Noble gas shorthand condenses the core electron configuration into the symbol of the preceding noble gas in square brackets. This saves time, reduces errors in long configurations, and is the standard format used in most textbooks and exams.

To use it: find the noble gas that comes just before your element in the periodic table, write its symbol in brackets, then write only the remaining electrons.

Example — Chlorine (Cl, Z=17):
Full: 1s² 2s² 2p⁶ 3s² 3p⁵
Preceding noble gas: Neon (Ne, Z=10) = 1s² 2s² 2p⁶
Shorthand: [Ne] 3s² 3p⁵

Example — Zinc (Zn, Z=30):
Full: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s²
Shorthand: [Ar] 3d¹⁰ 4s²

The noble gas shorthand also highlights valence electrons immediately. Everything outside the brackets is in the valence shell region, making it easy to predict bonding behavior.

Exceptions: Cr, Cu, and Why They Break the Rules

Chromium (Cr, Z=24) and Copper (Cu, Z=29) are the two most commonly tested exceptions to the Aufbau principle. Both involve the 3d and 4s subshells, and both occur because a half-filled or fully-filled d subshell is energetically more stable than the standard prediction.

Common electron configuration exceptions — Cr and Cu
Element Predicted Configuration Actual Configuration Reason
Chromium (Cr, Z=24) [Ar] 3d⁴ 4s² [Ar] 3d⁵ 4s¹ Half-filled d⁵ is extra stable (symmetry + exchange energy)
Copper (Cu, Z=29) [Ar] 3d⁹ 4s² [Ar] 3d¹⁰ 4s¹ Fully-filled d¹⁰ is extra stable

Other elements with similar exceptions include Molybdenum (Mo), Silver (Ag), Gold (Au), and several lanthanides and actinides. For most high school and introductory university courses, Cr and Cu are the only two you need to know by heart.

Exam Warning: If a multiple-choice question gives you [Ar] 3d⁴ 4s² for Cr, that is a trap. The correct answer is [Ar] 3d⁵ 4s¹. Examiners test this exception deliberately.

Common Mistakes and How to Fix Them

After reviewing thousands of student answers, I have identified five mistakes that account for the vast majority of lost marks in electron configuration problems.

Common electron configuration mistakes — wrong vs. right
# Mistake Wrong Correct
1 Filling 3d before 4s ..3p⁶ 3d² 4s² ..3p⁶ 4s² 3d²
2 Pairing electrons before half-filling (Hund’s violation) 2p: [↑↓][↑][ ] 2p: [↑][↑][↑]
3 Same spin when pairing (Pauli violation) [↑↑] [↑↓]
4 Ignoring Cr/Cu exceptions Cr: [Ar] 3d⁴ 4s² Cr: [Ar] 3d⁵ 4s¹
5 Removing wrong electrons for cations Fe²⁺: [Ar] 3d⁸ (removed from 3d) Fe²⁺: [Ar] 3d⁶ (removed from 4s)
Pro Tip: Always double-check your total electron count. Add up all the superscripts. The sum must equal the atomic number for neutral atoms, or atomic number minus charge for cations, or atomic number plus charge for anions.

Electron Configurations of Ions

Writing configurations for ions follows the same three rules, with one extra step: adjust the electron count for the charge, then remove or add electrons from the correct subshell.

For cations (positive charge, electrons removed): always remove electrons from the subshell with the highest principal quantum number first. For transition metals, this means removing from 4s before 3d, even though 4s filled first.

For anions (negative charge, electrons added): add electrons to the next available orbital following the Aufbau order.

Fe²⁺ (Iron loses 2 electrons):
Fe neutral: [Ar] 3d⁶ 4s²
Remove 2 electrons from 4s (highest n): [Ar] 3d⁶

Fe³⁺ (Iron loses 3 electrons):
Remove 2 from 4s, then 1 from 3d: [Ar] 3d⁵

Cl⁻ (Chlorine gains 1 electron):
Cl neutral: [Ne] 3s² 3p⁵
Add 1 electron to 3p: [Ne] 3s² 3p⁶ (same as Argon)

Notice that Fe³⁺ with [Ar] 3d⁵ has a half-filled d subshell — this is one reason Fe³⁺ is particularly stable compared to Fe²⁺.

Quick Quiz: Test Your Knowledge

Q1. What is the correct electron configuration for Sodium (Na, Z=11)?


Answer: B. Na has 11 electrons. Fill 1s² (2), 2s² (4), 2p⁶ (10), then the 11th electron goes into 3s¹. Noble gas shorthand: [Ne] 3s¹.

Q2. Which of the following correctly applies Hund’s rule to the 2p subshell with 2 electrons?


Answer: B. Hund’s rule requires one electron per orbital before pairing, and all single electrons must have parallel (same) spins. Option B shows [↑] [↑] [ ] — one electron in each of two orbitals, both spin-up. Option C has opposite spins, which violates Hund’s rule.

Q3. What is the actual (not predicted) electron configuration of Copper (Cu, Z=29)?


Answer: C. Cu is an exception. A fully-filled 3d¹⁰ subshell is extra stable, so one electron moves from 4s to 3d. The actual configuration is [Ar] 3d¹⁰ 4s¹, not the predicted [Ar] 3d⁹ 4s².

Practice Problems — Click to Reveal Answers

Problem 1: Write the full electron configuration for Phosphorus (P, Z=15).
Answer: 1s² 2s² 2p⁶ 3s² 3p³
Noble gas shorthand: [Ne] 3s² 3p³
Hund’s rule check (3p subshell): [↑] [↑] [↑] — three electrons, one per orbital, all parallel spins.
Valence electrons: 5 (3s² + 3p³)
Problem 2: Write the electron configuration for the Fe³⁺ ion.
Step 1 — Neutral Fe (Z=26): [Ar] 3d⁶ 4s²
Step 2 — Fe³⁺ loses 3 electrons: Remove 2 from 4s first, then 1 from 3d.
Answer: [Ar] 3d⁵
Note: This half-filled 3d⁵ configuration is particularly stable, which is why Fe³⁺ is a common oxidation state.
Problem 3: Identify the element with the configuration [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p⁴.
Step 1 — Count electrons: Xe (54) + 4f¹⁴ (14) + 5d¹⁰ (10) + 6s² (2) + 6p⁴ (4) = 54 + 30 = 84
Answer: Atomic number 84 = Polonium (Po)
Valence electrons: 6 (6s² + 6p⁴), placing it in Group 16 alongside oxygen and sulfur.
Problem 4: Write the configuration for the oxide ion O²⁻.
Neutral O (Z=8): 1s² 2s² 2p⁴
O²⁻ gains 2 electrons: Add 2 electrons to 2p.
Answer: 1s² 2s² 2p⁶ (same as Neon — isoelectronic with Ne)
This is why O²⁻ is stable: it achieves a noble gas configuration.

Sources & References

Reviewed by Dr. Irfan Mansuri. External links open in a new tab and are provided for further reading and verification.

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